Find the union, intersection, exclusive or, and complements of two independent events. A solver fills in the rest from any two values. Separate tabs cover a series of independent repeats and the area under a normal curve.
Formula
Independent events multiply:
P(A ∩ B) = P(A) × P(B)
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
P(A Δ B) = P(A) + P(B) − 2 × P(A ∩ B)
P(A') = 1 − P(A)
A series of n independent trials of A has
P(all n succeed) = P(A)^n
P(none succeed) = (1 − P(A))^n
P(at least once) = 1 − (1 − P(A))^n
A normal random variable with mean μ and standard deviation σ has
z = (x − μ) / σ
P(Lb ≤ X ≤ Rb) = Φ(z_Rb) − Φ(z_Lb)
Type -inf or inf for an unbounded side.
The default two-event example is P(A) = 0.5, P(B) = 0.4. Then P(A ∩ B) = 0.2, P(A ∪ B) = 0.7, and P(A Δ B) = 0.5. The events are assumed independent — the calculator does not handle conditional probability P(A|B).
Examples
Two independent events
P(A) = 0.5 and P(B) = 0.4. P(A') = 0.5, P(B') = 0.6, P(A ∩ B) = 0.2, P(A ∪ B) = 0.7, P(A Δ B) = 0.5, neither = 0.3.
Any two values
Given P(A) = 0.5 and P(A ∩ B) = 0.4, independence gives P(B) = 0.4 / 0.5 = 0.8, then P(A ∪ B) = 0.9.
Series of repeats
P(A) = 0.6 five times and P(B) = 0.3 three times. P(A occurs all five times) = 0.6^5 = 0.07776. P(A occurs at least once) = 0.98976.
Normal area from -1 to 1
On the standard normal (μ = 0, σ = 1) the area between −1 and 1 is 0.68269. P(X ≤ −1) = P(X ≥ 1) = 0.15866. Type inf for +∞; the area from −∞ to 1 is 0.84134.